Conteúdo apagado Conteúdo adicionado
Revisão das 20h31min de 7 de junho de 2015
1. Resolva os problemas abaixo (dica: transforme os logaritmos em potências):
1.
log
2
32
=
{\displaystyle \log _{2}32=}
6.
log
3
729
=
{\displaystyle \log _{3}729=}
11.
log
1
2
0
,
25
=
{\displaystyle \log _{\frac {1}{2}}0,25=}
16.
log
8
512
=
{\displaystyle \log _{8}512=}
2.
log
3
27
=
{\displaystyle \log _{3}27=}
7.
log
10
0
,
1
=
{\displaystyle \log _{10}0,1=}
12.
log
1
2
2
=
{\displaystyle \log _{\frac {1}{2}}2=}
17.
log
4
512
=
{\displaystyle \log _{4}512=}
3.
log
5
625
=
{\displaystyle \log _{5}625=}
8.
log
10
0
,
01
=
{\displaystyle \log _{10}0,01=}
13.
log
1
2
4
=
{\displaystyle \log _{\frac {1}{2}}4=}
18.
log
2
512
=
{\displaystyle \log _{2}512=}
4.
log
5
1
=
{\displaystyle \log _{5}1=}
9.
log
2
0
,
5
=
{\displaystyle \log _{2}0,5=}
14.
log
1
4
0
,
04
=
{\displaystyle \log _{\frac {1}{4}}0,04=}
19.
log
1
2
512
=
{\displaystyle \log _{\frac {1}{2}}512=}
5.
log
7
49
=
{\displaystyle \log _{7}49=}
10.
log
2
1024
=
{\displaystyle \log _{2}1024=}
15.
log
4
5
5
/
4
=
{\displaystyle \log _{\frac {4}{5}}5/4=}
20.
log
1
2
1024
=
{\displaystyle \log _{\frac {1}{2}}1024=}
